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Direction to solve :
The following line graph gives the percentage of the number of candidates who qualified an examination out of the total number of candidates who appeared for the examination over a period of seven years from 2004 to 2010





01. The difference between the percentages of candidates qualified to appear was maximum in which of the following pairs of years?
A. 2004 and 2009 B. 2007 and 2008
C. 2008 and 2009 D. 2009 and 2010 

Answer and Explanation

Answer: 2004 and 2009

Explanation:
from the given line graph, it is clear that the difference between the
=> Percentage of candidates qualified to appeared was maximum for the years 2004 and 2009 as 2004 has the minimum percentage while 2009 has the maximum percentage.

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02. In which pair of years was the number of candidates qualified the same?
A. 2005 and 2007 B. 2005 and 2010
C. 2008 and 2009 D. Data inadequate 

Answer and Explanation

Answer: Data inadequate 

Explanation:
we can’t determine the actual number of qualified candidates as we
=> Don’t know the number of appeared students

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03. If the number of candidates qualified in 2008 was 21200, what was the number of candidates appeared in 2008?
A. 32000 B. 28500
C. 26500 D. 25000

Answer and Explanation

Answer: 26500

Explanation:
let number of candidates appeared in 2008 be x,
=> Then, 80% of x = 21200
=> x = 21200 x 100/80 = 26500

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04. If the total number of candidates appeared in 2006 and 2007 together was 47400, then the total number of candidates qualified in these two years together was
A. 34700 B. 32100
C. 31500 D. Data inadequate

Answer and Explanation

Answer: Data inadequate

Explanation:
Data is inadequate to answer this question as we don’t
=> Know the number of candidates appeared in 2006 and in 2007, separately.

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05. The total number of candidates qualified in 2009 and 2010 together was 33500 and the number of candidates appeared in 2009 and 26500. What was the number of candidates appeared in 2010?
A. 24500 B. 22000
C. 20500 D. 19000

Answer and Explanation

Answer: 20500

Explanation:
Number of candidates appeared in 2009 = 26500
=>Therefore, number of candidates qualified in 2009
=> 80% of 26500 = 21200
=> Number of candidates qualified in 2010
=> 33500 – 21200 = 12300
=> Now, let the number of candidates appeared in 2010 be x.
=> Then, 60% of x = 12300
x = 12300 / 60 x 100 = 20500

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